KS3 · Maths
Perpendicular bisector of a line segment
No ruler markings, no protractor — yet your line has to hit the exact middle at exactly 90°. Sounds impossible? A pair of compasses and one clever shape do it every time.
Maths · Constructions
Every point on line PQ is the same distance from A as from B — so that's where equal arcs cross. And line PQ cuts AB into two equal halves at 90°.
AB is 12 cm. P is where two arcs of the same width — one from A, one from B — cross above AB, and Q is where two equal arcs cross below it. The faint lines show each compass width. They start at 9 cm, a sensible choice. Drag P or Q to try others: 7 cm works, but the crossing points crowd close to AB — and 20 cm wouldn't even fit on the page.
Why it works
Reason it through
Why does the line through the two crossing points cut AB in half at exactly 90°?
First link · your turn
Both sets of arcs use the same compass width. So what's true about each crossing point?
The quick way: arcs only
Problem
Construct the perpendicular bisector of a line segment AB that is 5.5 cm long, using arcs instead of full circles.
Predict, then check
Construct one side's bisector at a time, ignoring the other two sides while you work.
You construct the perpendicular bisector of each side of a triangle. What do the three lines do?
WHAT YOU'VE LEARNED
A quick recap of today's lesson.
Two equal arcs, one straight line — and the exact middle and the right angle come guaranteed.
What you need to know
- What 'bisect' and 'perpendicular' mean, and what a perpendicular bisector does to a line segment.
- How to construct a perpendicular bisector with a ruler and compasses, choosing a width that works.
- Why the construction works — the rhombus hiding inside it — and how to use it to find a triangle's circumcentre.
The big picture
The perpendicular bisector of a line segment cuts it into two equal halves at 90°. To construct it, draw arcs of the same width — more than half the segment — from both endpoints, then draw a line through the two points where they cross. It works because those points and the endpoints make a rhombus, whose diagonals always cross at right angles and cut each other in half.
Key points
Worked example
Problem
A line segment is 9.4 cm long. How long will each half be after you bisect it? And which of these compass widths would give you a perpendicular bisector: 3 cm, 4.7 cm or 6 cm?
⚠ Watch out
Putting the compass needle on the line but not exactly on an endpoint. The arcs still cross and the line still meets the segment at 90°, but it misses the midpoint — so you've drawn a perpendicular, not the perpendicular bisector.
Memory hook
Miss, touch, cross. Too narrow and the arcs miss; exactly half and they touch; wider than half and they cross twice — and the line through both crossings is your answer.
Check yourself
A line segment is 8 cm long. Would compasses set to 4 cm let you construct its perpendicular bisector? Say what would happen, and what you would change.
Flashcards
(12)What does 'bisect' mean?
What does 'perpendicular' mean?
What does the perpendicular bisector of a line segment do?
What is a rhombus?
What is special about the diagonals of a rhombus?
What is a construction?
How wide must the compasses be to bisect a line segment?
Not sure what width to use?
What is true about each point where the two sets of arcs cross?
Why must the line go through BOTH crossing points?
Why keep the construction arcs?
What is the circumcentre of a triangle?
Tap any card to flip it, or use Study as deck to go through them one at a time. In the full lesson these run as a spaced-repetition deck — you rate each card Hard, Good or Easy and the tricky ones keep coming back until they stick.
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Keep me postedMore KS3 Maths topics
- Adding and subtracting positive and negative integers
- Algebraic notation and conventions
- Angle sum in a triangle
- Angles on parallel lines (corresponding, alternate, co-interior)
- Area of a circle
- Area of a trapezium
- Area of a triangle
- Area of composite rectilinear shapes
- Arithmetic sequences and finding the nth term
- Associative, commutative and distributive laws
- Bisecting an angle
- Calculating theoretical probabilities
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