KS3 · Maths
Calculating theoretical probabilities
Two letters on a spinner, A and B. So landing on A is a 50–50 shot, right? Hold that thought. It's the trap this whole lesson is built to catch.
Maths · Probability
Six equal sectors, two letters
A spinner has six equal sectors. Five say A and one says B. Is landing on A a 50–50 shot? Do not answer yet. Sort each sector first, then read the counts.
Still to sort
Lands on A (0)
These sectors are in the event 'lands on A'.
Where the line is: Only sectors with an A on them. A sector with a B is not in this event.
Lands on B (not A) (0)
The opposite event to landing on A.
Where the line is: The sectors left over once the A sectors are taken out.
Five sectors say A and one says B. All six are the same size.
Maths · Probability
Can you find it by counting?
You can only find a theoretical probability when the individual outcomes are equally likely. Pick a trial, then decide which side it belongs on.
Still to sort
Theoretical probability can be found (0)
The individual outcomes are equally likely.
Where the line is: If you can say the individual outcomes are equally likely, you can count them.
Cannot be found (0)
The individual outcomes are not (or may not be) equally likely.
Where the line is: If the individual outcomes are not equally likely, counting outcomes does not give the probability.
The test is always the same: are the individual outcomes equally likely?
WHAT YOU'VE LEARNED
A quick recap of today's lesson.
Count the equally likely outcomes, not the labels.
What you need to know
- A theoretical probability counts the outcomes you want in a sample space where every individual outcome is equally likely.
- Write it as a fraction: outcomes in the event on top, total outcomes underneath. A fair dice gives P(5) = 1/6.
Have a goA spinner has five equal sectors labelled A to E. What is P(C)? Write it as a fraction.
1/5
One sector is C out of five equal sectors, so the event goes on top and the total underneath. Putting 5 on top flips the fraction upside down.
- When labels repeat, count every equal sector. Three A sectors and two B sectors give P(A) = 3/5 and P(B) = 2/5.
Have a goSam says: "Two letters, X and Y, so P(X) = 1/2. Easy." But the spinner has 4 equal sectors: three say X and one says Y. Fix Sam's answer.
P(X) = 3/4
Sam counted letters. The equally likely outcomes are the four sectors, and three of them say X.
- You can find a theoretical probability only if individual outcomes are equally likely. Bigger green cubes than blue? Then you can't.
- For a set of outcomes, count them all: on a fair dice, P(even) = 3/6 and P(not 4) = 5/6.
Have a goA fair dice is rolled. What is P(a number greater than 4)?
2/6
The numbers greater than 4 are 5 and 6, which is two outcomes out of six. Counting only one of them gives 1/6 and misses part of the set.
- Impossible events have probability 0 and certain events have probability 1. On a fair dice, P(7) = 0, P(not 7) = 1.
- Fractions, decimals and percentages all work: 3/5 = 0.6 = 60%.
- Whatever the form, a probability lies from 0 to 1, so a count of outcomes such as 3 isn't one.
- Expected number = probability × trials. With P(A) = 3/5, expect 300 As in 500 spins, but real results may differ by chance.
Have a goA fair dice is rolled 120 times. How many 4s do you expect?
20
P(4) = 1/6 and 1/6 of 120 is 20. That is only the expected number, so a real run of 120 rolls may give a different count.
- In frequency and outcome tables, it's the event's frequency or cells over the total, never over the number of categories.
The big picture
A theoretical probability counts the outcomes in your event over the total number of outcomes, but only when every individual outcome is equally likely. Count equal sectors, faces and cards rather than labels, then read the same count from a list, table, tree or Venn diagram.
Key points
Worked example
Problem
The cards 1 to 10 are shuffled and one is picked at random, so each card is equally likely. The cards are sorted into an outcome table by prime or not prime and odd or even. Find P(odd prime).
⚠ Watch out
Dividing by the number of labels instead of the number of equally likely outcomes. Two letters on a spinner doesn't make P(A) = 1/2, and 12 fudge sweets are not '12 out of the number of flavours'. Count the sectors, or use the total frequency.
Memory hook
Count the sectors, not the letters.
Check yourself
Cover the page. A spinner has 10 equal sectors and 4 say Z. Explain why P(Z) = 4/10, not 1/2. What would stop you finding it at all?
Flashcards
(14)What must be true before you can find a theoretical probability?
How is a theoretical probability written as a fraction?
A spinner has 8 equal sectors and 2 are red. What is P(red)?
The usual slip is dividing by the number of labels. What do you divide by instead?
Why is P(pizza) not necessarily 1/4 for a menu of four dishes?
What probabilities do impossible and certain events have?
Write 12/80 as a decimal and a percentage.
How do you find the expected number of times an outcome occurs?
In a frequency table, what goes underneath the fraction?
On a Venn diagram, what does P(not A) count?
What does P(only B) count on a Venn diagram?
How do you compare 35% and 5/12?
A tree for a six-sector spinner with five A sectors: why is the A branch 5/6?
The outcomes are 1 to 12 and P(A) = 1/4. How many outcomes are in A?
Tap any card to flip it, or use Study as deck to go through them one at a time. In the full lesson these run as a spaced-repetition deck — you rate each card Hard, Good or Easy and the tricky ones keep coming back until they stick.
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