KS3 · Maths
Expanding a single bracket
3 × 12 is 36, obviously. So why do so many people write 3(y + 2) = 3y + 2, which says it's 32? Let's make sure you never do.
Algebra · Expanding brackets
Equivalent or broken?
Does each expansion still equal the bracket it came from? Stuck? Put in a number, like 10, and work out both sides.
Still to sort
Equivalent: every term was multiplied (0)
Both sides give the same answer, whatever number you put in.
Where the line is: Swapping the order of an ADDITION is fine. Swapping the order of a SUBTRACTION is not.
Not equivalent: something went wrong (0)
A term escaped being multiplied, or a rule was bent.
Where the line is: It only takes one term that was not multiplied to break the whole expansion.
Eight students each expanded a bracket. Some kept the value exactly the same. Some quietly broke it. Sort them, then read why.
Predict, then check
Before you expand anything, look closely: both brackets are exactly the same.
3(x + 5) + 4(x + 5) is 3 lots of (x + 5) plus 4 lots of (x + 5). What does it simplify to?
WHAT YOU'VE LEARNED
A quick recap of today's lesson.
The term outside multiplies everything inside. Nobody gets left out.
What you need to know
- Expanding (or multiplying out) a bracket means writing an equivalent expression without the bracket.
- The term outside multiplies EVERY term inside: 3(x + 5) = 3x + 15, and 4(2a − 3b + 5) = 8a − 12b + 20.
- x × x = x², not 2x. Powers multiply the same way: x²(x + 1) = x³ + x², because x² × x = x × x × x.
- A negative multiplier changes the signs: −2(x + 5) = −2x − 10, and −5(x − 7) = −5x + 35, because a negative times a negative is positive.
- With more than one bracket, expand each bracket, then collect like terms: 2(x + 5) + 3(x + 6) = 2x + 10 + 3x + 18 = 5x + 28.
The big picture
Expanding a bracket means multiplying the term outside by every term inside, so the new expression is equal to the old one. Constants, letters, negatives and powers all follow the same rule: x × x = x², a negative multiplier changes the signs, and with two or more brackets you expand each one and then collect like terms.
Key points
Worked example
Problem
Expand 3y(x − 7 + 5y).
⚠ Watch out
Multiplying only the first term in the bracket, so 3(y + 2) becomes 3y + 2 instead of 3y + 6. The number outside multiplies everything inside, and a quick number test catches it: with y = 10, 3 × 12 is 36, not 32.
Memory hook
The term outside the bracket shakes hands with every term inside. Nobody gets left out, and the handshake is a multiply. If you are not sure, put in 10: if the two sides give different answers, the expansion is broken.
Check yourself
Cover the page. Expand a(a − 3) and 4(a + b + c + 3), then test one answer with a = 10. (Answers: a² − 3a and 4a + 4b + 4c + 12.)
Flashcards
(14)What does it mean to expand (or multiply out) a bracket?
In x + 5, which term is a constant and which is a variable?
How does the distributive law make 4 × 39 easier?
Why is 3(y + 2) not 3y + 2?
What is x × x?
How do 3(100 + 2) and 3(100 − 2) show what a subtraction inside a bracket does?
Do 4(x + y) and (y + x) × 4 mean the same thing?
Is 3(2 − a) the same as 3(a − 2)?
Expand −9(x − 3).
Expand y²(y + 4).
What are like terms?
What is the method for 6(x + 1) + 7(x + 3)?
Simplify 5(x − 7) + 2(x − 7) before expanding.
Simplify 10(x + 2) + 10(x + 4) using the matching multiplier.
Tap any card to flip it, or use Study as deck to go through them one at a time. In the full lesson these run as a spaced-repetition deck — you rate each card Hard, Good or Easy and the tricky ones keep coming back until they stick.
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Keep me postedMore KS3 Maths topics
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- Algebraic notation and conventions
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- Area of a triangle
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- Arithmetic sequences and finding the nth term
- Associative, commutative and distributive laws
- Bisecting an angle
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