GCSE · Physics · AQA · Spec 8463
Distance–time graphs
Read a graph line and you can tell exactly how fast something moved — no stopwatch needed.
What you need to know
- A straight sloping line on a distance–time graph means constant speed; gradient = speed.
- A horizontal line means the object is stationary — distance is not changing.
- A curve on the graph means the speed is changing — the object is accelerating or decelerating.
- Higher tier: find the speed at a specific instant on a curve by drawing a tangent at that point and calculating its gradient.
The big picture
A distance–time graph shows how far an object has travelled over time. The steeper the line, the faster the object is moving — gradient equals speed. A flat horizontal line means the object is stationary. A curve means the speed is changing (the object is accelerating or decelerating).
TONIGHT'S REVISION
Distance–time graphs
How to read gradient as speed — and spot acceleration from a curve.
Maths & Science · Interpret graphs
Reading a distance–time graph
Use the gradient tools to extract speed from each section of the journey.
Selected tool
Gradient (speed)
Reading
Gradient at t = 4s
Value
≈ 12.5 m/s
Pick two points on a straight section of the line. Read the change in distance (rise) and the change in time (run) from the axes. Speed = rise ÷ run.
Predict, then check
Look at each section description — commit to an answer before you reveal.
A distance–time graph has three sections: (1) a steep straight line, (2) a horizontal flat section, (3) a shallower straight line. Which section shows the object moving at its FASTEST speed?
How to find speed from a distance–time graph
Follow every step in order — this is the method examiners expect to see written down.
Relationship matrix
Tap any cell to reveal it. Tap a column header to read one property down every item.
Each cell hides a short answer and the reason behind it. Predict before you tap.
Process · Closed loop
Higher tier: Finding instantaneous speed from a curve
Use this repeatable cycle whenever the distance–time graph is curved.
Stage 01
Locate the point
Find the exact point on the curve where you need the instantaneous speed. Mark it clearly with a dot.
AQA Paper 2 — exam technique
AQA mark-scheme practice
Does this student answer contain the phrases that unlock marks?
Question
Describe the motion shown by the distance–time graph. Section A: steep straight line for 10 s. Section B: horizontal line for 5 s. Section C: shallower straight line for 10 s.
Student answer
In section A the object moves at constant speed. In section B the object is stationary. In section C the object moves at constant speed but more slowly than in section A.
Equations you need
Taken directly from the exam-board specification.
v = speed (m/s) · s = distance (m) · t = time (s)
Learn it — you must recall this in the exam
Key points
Worked example
Problem
A cyclist travels 600 m in 40 s at constant speed. What is the cyclist's speed? Show how you would read this from a distance–time graph.
Memory hook
STEEP = SPEEDY, FLAT = FROZEN, CURVE = CHANGING — three words that cover every line shape you will ever see on a distance–time graph.
★ Exam tip
On AQA Paper 2, always show your gradient calculation with a clearly labelled rise-and-run triangle drawn on the graph — examiners award a method mark for the working even if you misread a value. Higher tier: when drawing a tangent to a curve, extend the line as far as possible across the graph before reading off rise and run, to minimise reading errors.
⚠ Watch out
Confusing a steep straight line with acceleration — a steep straight line is FAST CONSTANT SPEED, not speeding up. Only a CURVE means the speed is changing.
Check yourself
Without looking — sketch what a distance–time graph looks like for an object that travels fast, then stops, then travels slowly. What are the three key features of your sketch?
Flashcards
(22)What does the gradient of a distance–time graph equal?
What does a straight sloping line on a distance–time graph show?
What does a horizontal (flat) line on a distance–time graph show?
What does a curve on a distance–time graph show?
Write the equation for speed.
What are the units of speed when distance is in metres and time is in seconds?
A steeper gradient on a distance–time graph means what?
Two objects have straight lines on the same distance–time graph. Object A has a steeper line. What does this mean?
Higher tier: How do you find the speed of an object at a specific instant when the distance–time graph shows a curve?
Higher tier: Why must you draw a tangent to find speed on a curved distance–time graph?
What does a decreasing gradient on a distance–time graph tell you about the object's motion?
An object's distance–time graph shows a horizontal line for 5 s. What is its speed during this time?
How do you calculate the gradient of a straight line on a distance–time graph?
A car travels 300 m in 20 s at constant speed. What is its speed?
What shape is the line on a distance–time graph for a uniformly accelerating object?
Higher tier: On a curved distance–time graph, what does a steeper tangent drawn at a later time indicate?
What two quantities do you need to read from the graph axes to calculate speed?
Higher tier: What is meant by 'instantaneous speed' on a distance–time graph?
An object's distance–time graph shows a curve that gets progressively steeper. What is happening to the object?
Which AQA paper assesses distance–time graphs?
A distance–time graph has gradient = 0. What does this tell you about the object?
If the gradient of a straight section of a distance–time graph is 12, what is the object's speed?
Tap any card to flip it, or use Study as deck to go through them one at a time. In the full lesson these run as a spaced-repetition deck — you rate each card Hard, Good or Easy and the tricky ones keep coming back until they stick.
Learn Distance–time graphs properly — interactive practice, marked questions and flashcards.
Start this lesson freeMore AQA GCSE Physics topics
- Acceleration (a = Δv/t)
- Current, resistance and potential difference (V = I R)
- Density of materials (ρ = m/V)
- Distance and displacement
- Efficiency
- Energy stores and systems
- Gravitational potential energy (Ep = m g h)
- Kinetic energy calculation (Ek = 1/2 m v^2)
- Newton's First Law
- Newton's Second Law (F = m a)
- Power (P = E/t and P = W/t)
- Resultant forces and resolving forces
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