GCSE · Maths · OCR · Spec J560
Grouped data
Squash 200 different answers into five neat rows and the table looks lovely, but something has gone missing. What, and what can you still work out anyway?
Finding the median class
Problem
48 pupils were asked how many texts they sent in one day, grouped: 0 ≤ n < 10: 7 10 ≤ n < 20: 15 20 ≤ n < 30: 18 30 ≤ n < 40: 8 Find the median class.
WHAT YOU'VE LEARNED
A quick recap of today's lesson.
A grouped table is tidy, but it has quietly thrown the exact values away. Here's what you can still find out from it.
What you need to know
- A grouped frequency table shows how many values fall in each interval (also called a group or class), not the values themselves.
- The row 40 ≤ x < 50 holds values from 40 up to, but not including, 50. So 50 itself is excluded.
Have a goJas insists every number from 39 to 50 fits in the row 40 ≤ x < 50. Which of 39, 40, 49 and 50 prove Jas wrong?
39 and 50
39 is below 40, and 50 is excluded because of the < sign. The ≤ at the bottom keeps 40 in, and 49 is comfortably inside.
- With whole-number data, that same row covers just 40, 41, and so on up to 49.
- Once values are grouped, the exact value of each data point is lost, so the mean and range can only be estimated.
- Add up the frequency column and you get the total number of data points.
Have a goA grouped table has frequencies 3, 8, 5 and 4. How many data points are in the data set?
20
The frequency column adds up to the number of data points. Counting the 4 rows would count rows, not data.
- Intervals don't all have to be the same size, and neighbouring low-frequency intervals can be combined into one larger one.
- The modal class is the interval with the highest frequency. Different groupings of the same data can give different modal classes.
- Median class: work out the position (total frequency + 1) ÷ 2, then find where the running total first reaches it.
Have a goThe frequencies in a table add up to 40. What is the median position?
20.5
(40 + 1) ÷ 2 = 20.5. Halving 40 to get 20 forgets the + 1.
- Estimate the mean: midpoint × frequency for each row, add them up, then divide by the total frequency.
- Two range estimates: the maximum possible range uses the bounds, the average expected range uses the midpoints.
The big picture
A grouped frequency table gives the frequency of each interval instead of each value, so the exact values are lost. You can still read off the modal class and find the median class, and you can estimate the mean (midpoint × frequency, divided by the total frequency) and the range.
Key points
Worked example
Problem
20 pupils recorded their weekly reading time (t minutes), grouped: 0 ≤ t < 10: 3 10 ≤ t < 20: 9 20 ≤ t < 30: 6 30 ≤ t < 50: 2 Find the modal class, the median class and an estimate of the mean.
⚠ Watch out
Giving a frequency or a midpoint as the modal class (it should be an interval), and dividing the total of midpoint × frequency by the number of rows instead of by the total frequency.
Memory hook
Mean needs Midpoints: midpoint × frequency, add up, then divide by the total frequency, never by the number of rows.
Check yourself
Without looking back: explain to an imaginary friend why 50 is not in the row 40 ≤ x < 50, and why a grouped table can never tell you the exact mean.
Flashcards
(11)What does a grouped frequency table show?
Which values does the row 40 ≤ x < 50 hold?
What can't you know from a grouped frequency table?
What does the sum of the frequency column tell you?
Must every interval in a table be the same size?
How do you give the modal class?
How do you find the median class?
What are the steps to estimate a mean from a grouped table?
An estimated total of £6,320 from 139 people: what is the estimated mean?
How can you tell an estimated mean is believable?
What are the two estimates of the range from a grouped table?
Tap any card to flip it, or use Study as deck to go through them one at a time. In the full lesson these run as a spaced-repetition deck — you rate each card Hard, Good or Easy and the tricky ones keep coming back until they stick.
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