GCSE · Chemistry · AQA · Spec 8462
Volumes of gases (chem HT)
A mole of carbon dioxide weighs 22 times as much as a mole of hydrogen. At room temperature and pressure, which fills more space? Neither. Exactly the same volume.
Chemistry · Moles and gas volume
Drag the amount of gas from 0 to 3 moles. One readout is for hydrogen, the other for carbon dioxide, both at room temperature and pressure. Do they ever split apart? Then run it backwards: find the amount of gas that fills 42 dm³.
From grams to dm³ — and back again
Questions often hand you a mass, but gas volume follows moles — so count the moles first. Example: 3.4 g of ammonia, NH₃ (Mr = 17). 3.4 ÷ 17 = 0.20 mol.
Reacting volumes: let the equation do the work
Problem
Carbon monoxide burns in oxygen: 2CO(g) + O₂(g) → 2CO₂(g). What volume of oxygen reacts with 60 cm³ of carbon monoxide, and what volume of carbon dioxide forms? All the volumes are measured at the same temperature and pressure.
WHAT YOU'VE LEARNED
A quick recap of today's lesson.
Count the moles and you know the volume — whichever gas it is.
What you need to know
- Equal amounts in moles of gases take up the same volume when they're at the same temperature and pressure.
- Room temperature and pressure (RTP) means 20 °C and 1 atmosphere. At RTP, one mole of any gas has a volume of 24 dm³.
- Volume in dm³ = moles × 24. Change the subject and you get moles = volume in dm³ ÷ 24.
- From a mass: moles = mass ÷ Mr, then multiply by 24 to get the volume at RTP.
- 1 dm³ = 1000 cm³, so convert a volume in cm³ to dm³ (divide by 1000) before you use 24.
- For gases reacting at the same temperature and pressure, the balanced equation's mole ratio is also their volume ratio.
The big picture
At the same temperature and pressure, equal amounts in moles of gases take up the same volume, whichever gases they are. At room temperature and pressure (RTP: 20 °C and 1 atmosphere), one mole of any gas fills 24 dm³, so volume in dm³ = moles × 24, and moles = volume ÷ 24. To get from the mass of a gas to its volume, divide by the relative formula mass to find the moles, then multiply by 24. In a reaction between gases at the same conditions, the balanced equation's mole ratio is also the ratio of their volumes.
Key points
Worked example
Problem
Calcium carbonate reacts with excess hydrochloric acid: CaCO₃(s) + 2HCl(aq) → CaCl₂(aq) + H₂O(l) + CO₂(g). What volume of carbon dioxide, at room temperature and pressure, is made from 5.0 g of calcium carbonate? (Mr of CaCO₃ = 100)
⚠ Watch out
Forgetting to convert cm³ to dm³ before using 24. For 600 cm³ of gas, 600 ÷ 24 = 25 mol is wildly wrong. Convert first: 600 cm³ = 0.600 dm³, and 0.600 ÷ 24 = 0.025 mol. (Or divide the cm³ by 24 000 in one go.)
Memory hook
Count moles, not grams. One mole, any gas, 24 dm³ at RTP — and between gases, the equation's big numbers are the volume ratio.
Check yourself
At RTP, what volume do 1.5 mol fill? How many moles fill 60 dm³? In N₂(g) + O₂(g) → 2NO(g), 10 cm³ of N₂ makes how much NO? (36 dm³; 2.5 mol; 20 cm³)
Flashcards
(11)What volume does one mole of any gas occupy at room temperature and pressure?
What conditions does room temperature and pressure (RTP) mean?
Two gas samples at the same temperature and pressure have the same volume. What else must be the same about them?
Does a heavier gas take up more volume per mole?
How do you find the amount in moles of a gas from its volume at RTP?
What is the route from the mass of a gas to its volume at RTP?
How many cm³ are there in 1 dm³?
For gases reacting at the same temperature and pressure, what does the balanced equation tell you about their volumes?
When can't you use the equation's numbers directly as a volume ratio?
Sense check: is 30 dm³ of gas at RTP more or less than 1 mole?
How do you change the subject of an equation?
Tap any card to flip it, or use Study as deck to go through them one at a time. In the full lesson these run as a spaced-repetition deck — you rate each card Hard, Good or Easy and the tricky ones keep coming back until they stick.
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