GCSE · Chemistry · AQA · Spec 8462
Atom economy
Heat calcium carbonate and, however carefully you work, only part of its mass can become calcium oxide. The balanced equation sets that share before anything reacts.
Chemistry · Atom economy
CaCO₃ → CaO + CO₂. Relative formula masses: CaCO₃ = 100, CaO = 56, CO₂ = 44. The masses shown assume all the calcium carbonate reacts.
Worked calculation
Problem
Iron is made by this reaction: Fe₂O₃ + 3CO → 2Fe + 3CO₂. Calculate the percentage atom economy for iron. (Relative atomic masses: Fe = 56, C = 12, O = 16)
WHAT YOU'VE LEARNED
A quick recap of today's lesson.
What you need to know
- Atom economy (also called atom utilisation) measures how much of the starting materials end up as useful products.
- Percentage atom economy = (relative formula mass of desired product from equation ÷ sum of relative formula masses of all reactants from equation) × 100.
- Take every mass from the balanced equation: multiply by each coefficient and include every reactant.
- Atom economy depends on which product is wanted and does not change with the amount you make.
- High atom economy matters for sustainable development and for economic reasons.
- Higher only: a reaction pathway is chosen by weighing atom economy together with yield, rate, equilibrium position and usefulness of by-products.
The big picture
Atom economy is a measure of the amount of starting materials that end up as useful products. It is calculated from the balanced equation: the relative formula mass of the desired product, divided by the sum of the relative formula masses of all the reactants, multiplied by 100. Because it comes from the equation, it is fixed before the reaction is run, whatever the scale, and it depends on which product is wanted. Reactions with a high atom economy turn less of their starting materials into unwanted products, which is important for sustainable development and for economic reasons.
Key points
Worked example
Problem
Sodium hydrogencarbonate decomposes when heated: 2NaHCO₃ → Na₂CO₃ + H₂O + CO₂. Calculate the percentage atom economy for sodium carbonate. (Relative atomic masses: Na = 23, H = 1, C = 12, O = 16)
⚠ Watch out
Dividing by the unwanted products instead of by all the reactants. For heating calcium carbonate, 56 ÷ 44 × 100 gives 127%, which is impossible: the bottom of the fraction must be the total mass of ALL the reactants, 100.
Memory hook
Want over all, times a hundred: the product you WANT on top, ALL the reactants underneath, coefficients included.
Check yourself
2H₂O₂ → 2H₂O + O₂, with oxygen as the desired product. Using H₂O₂ = 34 and O₂ = 32, what is the percentage atom economy? (32 ÷ (2 × 34) × 100 = 47.1%)
Flashcards
(9)What does atom economy measure?
In the atom economy fraction, what goes on top and what goes underneath?
Why must you use the coefficients in the balanced equation?
What is the atom economy of a reaction whose only product is the desired product?
If you make ten times as much product, what happens to the atom economy?
Can the same reaction have two different atom economies?
A reaction goes perfectly and none of the product is lost. Is its atom economy 100%?
Why are reactions with a high atom economy preferred?
Higher only: besides atom economy, what data help decide which reaction pathway to use?
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