GCSE · Maths · Edexcel · Spec 1MA1 · Foundation+Higher

Geometrical problems on coordinate axes

Two lines on squared paper look square to each other. Your eyes say yes. Two numbers can say yes or no for certain, even when the drawing is wonky.

Swing line B until it is square to line A

-20.535.58-20246xy4.00gradient A × gradient Blift or lower me
Gradient of line B 2

Gradient of line B: 2. gradient A × gradient B: 4.00

Red line A has gradient 2. It stays put. Line B starts parallel to it, because the two gradients are equal. Swing B round: when B’s gradient is −1/2 the product reads −1.00 and the lines cross at a right angle. At any other gradient the product is not −1 and the angle is not square.

Both axes use the same scale. Lift or lower the dot to swing line B round.

Watch out: Perpendicular lines only look perpendicular when the scales on the two axes are in the ratio 1 : 1. On skewed axes, gradients read from a drawn construction will not be negative reciprocals, so check the scales before you trust a picture.

Maths · Gradient

Where does this answer go wrong?

Are the line through A(−2, 5) and B(4, −1) and the line through C(0, −3) and D(6, −9) parallel? A student answered like this. Which line is the first to go wrong?

A student’s answer — which line goes wrong?

Maths · Perpendicular bisector

Build the perpendicular bisector

A is the point (−3, 2) and B is the point (5, 6). Find an equation of the perpendicular bisector of the line segment AB.

  1. The perpendicular bisector cuts AB exactly in half at a right angle. So it needs two things: the negative reciprocal of AB’s gradient, and the midpoint of AB to pass through.
  2. Gradient of AB = (6 − 2) ÷ (5 − (−3)) = 4 ÷ 8 = 1/2.
  3. missing step
Which line is step 3?

Maths · Dividing a segment

Where does P sit on AB?
02468drag P along AB →

P along AB: 1/4. x distance from A 2. y distance from A 3. P is at (4, 4)

Fraction1/4AP : PB1 : 3x distance from A2y distance from A3P is at(4, 4)

A is (2, 1) and B is (10, 13). Drag P along AB and watch the ratio, the x distance and the y distance move together.

Watch out: Check which ratio you are given. AP : PB = 1 : 3 puts P a quarter of the way along AB, but AP : AB = 1 : 3 would put it a third of the way along.

Maths · Shapes on axes

What does this evidence prove?

Pick a piece of evidence about a quadrilateral, then choose the shape it proves. Some evidence proves nothing yet.

Still to sort

Parallelogram (0)

Two pairs of parallel sides.

Where the line is: Add a right angle between adjacent sides and it is a rectangle.

Rectangle (0)

A parallelogram with adjacent sides perpendicular.

Where the line is: Add perpendicular diagonals and it is a square.

Rhombus (0)

A parallelogram with perpendicular diagonals.

Where the line is: Perpendicular diagonals count once the sides are parallel, or the diagonals bisect each other.

Square (0)

A rectangle whose diagonals meet at right angles.

Not enough yet (0)

A fact that more than one shape shares.

Where the line is: A kite also has diagonals that meet at right angles, but they do not bisect each other.

6 of 6 still to sort.

Maths · Proving a shape

Write the proof

The points A(1, 1), B(5, 3), C(4, 5) and D(0, 3) are the corners of the quadrilateral ABCD. Show that ABCD is a rectangle. [4 marks]

0 words · your answer stays on this page and is not sent anywhere.

Exam line: The perpendicular-gradient ideas in this lesson may sit in the Higher tier of Edexcel 1MA1, so check which tier your papers cover.

WHAT YOU'VE LEARNED

A quick recap of today's lesson.

m₁ × m₂ = −1

Perpendicular lines: the gradients multiply to −1. Parallel lines: the gradients are equal.

What you need to know

  • Gradient is the change in y divided by the change in x, both worked out the same way round.
  • Parallel lines have the same gradient.
  • Have a goYour mate swears the line through (1, 2) and (3, 8) is parallel to a line with gradient 2, because they “look about the same”. Do the numbers agree?

    No. The gradient is (8 − 2) ÷ (3 − 1) = 3, not 2.

    Parallel means exactly the same gradient. “Looks about the same” is how a gradient of 3 sneaks past a gradient of 2.

  • Perpendicular lines have gradients that multiply to −1: negative reciprocals, like 2 and −1/2.
  • Have a goA line has gradient 5. What gradient does a line perpendicular to it have?

    −1/5

    Flip 5 to get 1/5, then change the sign. Flipping alone gives 1/5, and 5 × 1/5 is +1, which is not the −1 that perpendicular needs.

  • For a perpendicular line through a point, use the negative reciprocal as m, then substitute the point into y = mx + c.
  • A perpendicular bisector is perpendicular to the segment and passes through its midpoint: halve the x and y journeys from A.
  • AP : PB = 1 : 3 gives 4 equal parts, so P is a quarter of the way from A.
  • Have a goSam sees AP : PB = 1 : 4 and says, “P is a quarter of the way along AB.” Where does Sam go wrong?

    1 + 4 = 5 equal parts, so P is one fifth of the way from A.

    The ratio compares the two pieces, AP and PB. The whole of AB is both pieces together, so add them to count the equal parts.

  • Lines only look perpendicular when the axes have a 1 : 1 scale, so check the scales before trusting a drawing.
  • Have a goYou plot lines with gradients 2 and −1/2 on axes whose scales are not in the ratio 1 : 1. Will the drawn lines look perpendicular?

    No. On skewed scales the drawn lines will not look perpendicular.

    Their gradients multiply to −1, but gradients read from a drawing on skewed axes are not negative reciprocals, so the picture stops showing it. Check the scales first.

  • Two pairs of equal opposite-side gradients make a parallelogram; add adjacent gradients multiplying to −1 and it is a rectangle.
  • A parallelogram with perpendicular diagonals is a rhombus, but perpendicular diagonals alone are not enough: a kite has them too.
  • To prove a shape’s type, show every step and explain it; to disprove it, one failed property is enough.

The big picture

On coordinate axes, geometry turns into arithmetic. Gradients decide whether lines are parallel or perpendicular, midpoints and ratios place points on a segment, and those same tools prove which quadrilateral a set of points makes.

Key points

1Gradient = change in y ÷ change in x. Subtract in the same order on the top and the bottom.
2Parallel: equal gradients. Perpendicular: gradients multiply to −1.
3Perpendicular line through a point: negative reciprocal gradient, then substitute the point into y = mx + c to find c.
4Midpoint: start at A and add half of the x journey and half of the y journey to B.
5AP : PB = 1 : 3 means 4 equal parts, and P is a quarter of the way from A. The ratio applies to both the x and the y distances.
6Parallelogram: equal gradients on opposite sides. Rectangle: also adjacent gradients multiplying to −1. Rhombus: a parallelogram with perpendicular diagonals.

Worked example

Problem

A is the point (−3, −5) and B is the point (7, 10). P is on the line segment AB with AP : PB = 2 : 3. Find the coordinates of P.

⚠ Watch out

Trusting the picture. Lines that look parallel or square, or diagonals that look perpendicular, prove nothing. Calculate the gradients and midpoints, and show each property the shape needs.

🧠

Memory hook

Perpendicular: flip it and flip its sign. 2 becomes −1/2.

✓

Check yourself

Close the page and say from memory how you test two lines for parallel, how you test for perpendicular, and what you check about the axes before you trust a diagram.

Flashcards

(13)
How do you find the gradient of a line segment from its end points?
Change in y ÷ change in x, both worked out the same way round (end minus start). Take care with negative values.
Parallel lines: what is true of their gradients?
The gradients are equal.
Perpendicular lines: what is true of their gradients?
They multiply to −1. Each is the negative reciprocal of the other: opposite sign, and reciprocals.
What is the negative reciprocal of 3/4?
−4/3. Flip the fraction and change the sign: 3/4 × (−4/3) = −1.
Method for an equation of the line perpendicular to a given line through a given point?
Use the negative reciprocal gradient as m in y = mx + c, then substitute the point’s x and y to find c.
What does a perpendicular bisector do to a line segment?
It cuts the segment exactly in half at a right angle, so it is perpendicular to the segment and passes through its midpoint.
How do you find the midpoint of the segment from A to B?
Halve the x journey and the y journey from A to B, then add them to A’s coordinates. It is where P lands when AP : PB = 1 : 1.
AP : PB = 2 : 5. What fraction of the way from A to B is P?
2 + 5 = 7 equal parts, so P is 2/7 of the way from A. Apply that fraction to the x distance and to the y distance.
Why should you not trust a drawing to show two lines are perpendicular?
Lines only look perpendicular on axes with scales in the ratio 1 : 1. On skewed scales, gradients read from the drawing are not negative reciprocals.
What do you show to prove a quadrilateral is a parallelogram? A rectangle?
Parallelogram: opposite sides have equal gradients (two pairs of parallel sides). Rectangle: also adjacent sides perpendicular, with gradients multiplying to −1.
Which shapes can perpendicular diagonals help you prove?
A parallelogram whose diagonals are perpendicular is a rhombus. A rectangle whose diagonals meet at right angles is a square.
Why do perpendicular diagonals alone not prove a rhombus?
A kite also has diagonals that meet at right angles, but they do not bisect each other. Show parallel sides, or that the diagonals bisect each other.
How do you show a shape is not a given type?
Show that one required property fails. For example, opposite sides with different gradients are not parallel.

Tap any card to flip it, or use Study as deck to go through them one at a time. In the full lesson these run as a spaced-repetition deck — you rate each card Hard, Good or Easy and the tricky ones keep coming back until they stick.

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